14x-40x^2=0

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Solution for 14x-40x^2=0 equation: 



14x-40x^2=0

a = -40; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·(-40)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*-40}=\frac{-28}{-80}
=7/20
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*-40}=\frac{0}{-80}
=0
$

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